CrazCo Posted January 19, 2009 Posted January 19, 2009 Tn = 3/4n^2 -9 what is the common difference of said series/sequence the answer is 3/2 and i dont know how it is. i thought common different was just what each term differs by so i replaced n with numbers to get t1=-8.25 t2= -6 t3= -2.25 and i dont see anything common. guidance?
D H Posted January 19, 2009 Posted January 19, 2009 guidance? http://www.purplemath.com/modules/nextnumb2.htm Let me know if that answers your questions.
CrazCo Posted January 20, 2009 Author Posted January 20, 2009 sort of, but it more so was the stuff i already know about common difference. the specific sequence above is what i dont get
D H Posted January 20, 2009 Posted January 20, 2009 You keep taking differences until you arrive at a common term. This will always happen for any series that can be expressed as a polynomial. The first differences for the series at hand are [math]\Delta_1 t_n \equiv t_{n+1} - t_n = (3/4(n+1)^2 -9) - (3/4n^2 -9) = 3/2n+3/4[/math] That's not constant, so take the second difference: [math]\Delta_2 t_n \equiv \Delta_1 t_{n+1} - \Delta_1 t_n[/math] This is constant, so the result is your common difference.
CrazCo Posted January 21, 2009 Author Posted January 21, 2009 ohhhh so linear you go to the first difference, quadratic you go to the second difference, and cubic the third i feel so dumb now! thanks!
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