transgalactic Posted January 26, 2009 Posted January 26, 2009 http://img265.imageshack.us/img265/5461/63848612xp9.gif
jian Posted January 28, 2009 Posted January 28, 2009 It should be 1 Firstly take the logarithm of original expression. ln([sin(x)]^x)=xln(sinx)=(ln(sinx))/(1/x) take the derivative of both the denominator and numerator got lim(-xcosx)*(x/sinx)=lim(-xcosx)=0 when x approaches to 0. so the original limit will be 1. limits.doc
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