blazinfury Posted January 30, 2009 Share Posted January 30, 2009 A high fountain of water is located at the center of a circular pool as in the figure below. Not wishing to get his feet wet, a student walks around the pool and measures its circumference to be 25.0 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation at the bottom of the fountain to be 55.0°. How high is the fountain? I did: 2(pi)r=25 r=39.27 m y=39.27sin(55)=32.17 m However i was wrong. Any advice. Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted January 30, 2009 Share Posted January 30, 2009 I don't see how you can get a radius bigger than your circumference. [math]2\pi r = 25[/math] [math]r = \frac{25}{2 \pi}[/math] which should be less than 25. Try that and see if you get the right answer. Link to comment Share on other sites More sharing options...
CaptainPanic Posted January 30, 2009 Share Posted January 30, 2009 I don't see how you can get a radius bigger than your circumference. [math]2\pi r = 25[/math] [math]r = \frac{25}{2 \pi}[/math] which should be less than 25. Try that and see if you get the right answer. The error was probably just typing it wrong on the calculator: To get the answer of [math]r = \frac{25}{2 \pi}[/math] you have to type on the calculator is 25, divide by 2, divide by pi. The result of 39.27 comes from 25, divide by 2, multiply by pi. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now