Fortissimo Posted February 1, 2009 Share Posted February 1, 2009 Could someone explain to me how the total number of molecules of water produced for the complete oxidation of palmitoyl coA to water and CO2 is calculated? Link to comment Share on other sites More sharing options...
CaptainPanic Posted February 2, 2009 Share Posted February 2, 2009 If you completely oxidize any hydrocarbon (containing C, H, possibly O), then there will be only 2 products: CO2 and H2O. Therefore, all the hydrogen (H) will form water (H2O) All the carbon © will form carbon dioxide (CO2). Now all you have to do is to calculate the amount of H and C in the palmitoyl coA to get the answer. Note that there is already a little oxygen on the fatty acid (the acid group), so if you need to know how much oxygen you must add, subtract those oxygens to get an answer to that. Link to comment Share on other sites More sharing options...
Fortissimo Posted February 5, 2009 Author Share Posted February 5, 2009 Yeah I know all that but in oxidative phosphorylation, isn't a molecule of water formed per condensation of ADP and inorganic P? Link to comment Share on other sites More sharing options...
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