Tracker Posted February 1, 2009 Share Posted February 1, 2009 This is a question I have worked on in Stats and my answer does not line up with the solution manuals. [math] P(A' \cap B' \cap C) = P© - P(A \cap C) - P(B \cap C) + P(A \cap B \cap C) [/math] My answer there is a negative before [math] P(A \cap B \cap C) [/math] Link to comment Share on other sites More sharing options...
Samar Posted February 2, 2009 Share Posted February 2, 2009 I'm afraid your solution manuals is correct. This is the Venn diagram of your problem. What you want to do is to say P© without that region of intersection with A alone,B alone + the region of intersection of three circles.Right? but when you say [math]P(A \cap C)[/math] you refer to the region in which A intersects C alone + that one in which the three circles intersect with each other. And when you say [math] P(B \cap C) [/math] you also refer to the region in which B intersects with C alone + that one in which the three circles intersect. If you added both values to each other with negative before them you'd be saying:It's the probability of C without regions of intersecion with A alone + B alone + 2 times the region of intersection of three circles. That's why you compensate that by adding [math]P(A \cap B \cap C)[/math] with positive before it at the end of the equation. I hope this helped Link to comment Share on other sites More sharing options...
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