Ashish Posted February 5, 2009 Posted February 5, 2009 In order to show unpolarized light we use the can you tell me please about what this arrow on the unpolarized represent whether it represent electric field or what?
insane_alien Posted February 5, 2009 Posted February 5, 2009 either electric or magnetic field, it doesn't really matter.
Ashish Posted February 5, 2009 Author Posted February 5, 2009 can you tell me why? I've read its electric field
Klaynos Posted February 5, 2009 Posted February 5, 2009 The direction of the electric field vector is the definition of polarisation.
swansont Posted February 5, 2009 Posted February 5, 2009 By convention it's the electric field; the magnetic field will always be at 90º so there's no need to depict it. Edit: Gah! One minute late! Kurse you, Klaynos!
timo Posted February 5, 2009 Posted February 5, 2009 I have a follow-up question on polarization of light. Assume I want to polarize microwaves with a metal grate. Assume the grate is oriented such that the bars of the grate are vertically aligned. Staying in the definition above: What will be the polarization of the beam of microwaves after the grate - and why?
Klaynos Posted February 5, 2009 Posted February 5, 2009 I think... Perpendicular to the grating, the E field induced a charge in the grating along it's axis, and gets absorbed through non-radiative damping. I wonder though about the diffraction through these slits, or if they're below the diffraction limit, the surface plasmon polaritons you would create and their associated fields... I will check with a microwave physicist in the morning
swansont Posted February 6, 2009 Posted February 6, 2009 Apply the boundary conditions. The perpendicular component of the field has to go to zero for a conductor where there is no net charge, and the parallel component suffers no discontinuity. This assumes that the perpendicular direction can't support the wave, i.e. it's smaller than the wavelength.
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