Jump to content

Recommended Posts

Posted

29081539pt7.th.gif

 

 

so my general function are bigger then their taylor series by the remainder of Rn

the functions are greater than the Taylor polynomial up to power n

by the members which are in a higher powers then "n"

this is the logic

how to formulate it into equation??

Posted

i got the idea that its the function is bigger then the polynomial by the members with powers higher then "n".

 

but its only a logic

how to formulate it into mathematical equations??

 

the remainder formula is

0<c<x

[math]

R_n(x)=\frac{f^{n+1}©}{(n+1)!}x^{n+1}

[/math]

 

so i guess that for x>0 its:

[math]

R_n(x)=\frac{f^{n+1}©}{(n+1)!}x^{n+1}

[/math]

 

for x<0

[math]

R_n(x)=-\frac{f^{n+1}©}{(n+1)!}x^{n+1}

[/math]

 

should i prove it by induction??

if so then if n=1 then

[math]

e^x=1+x+ \frac{f^{1+1}©}{(1+1)!}x^{1+1}

[/math]

 

but i dont know whats the value of c??

and still it depends on the values of x

??

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.