transgalactic Posted February 13, 2009 Posted February 13, 2009 so my general function are bigger then their taylor series by the remainder of Rn the functions are greater than the Taylor polynomial up to power n by the members which are in a higher powers then "n" this is the logic how to formulate it into equation??
transgalactic Posted February 15, 2009 Author Posted February 15, 2009 i got the idea that its the function is bigger then the polynomial by the members with powers higher then "n". but its only a logic how to formulate it into mathematical equations?? the remainder formula is 0<c<x [math] R_n(x)=\frac{f^{n+1}©}{(n+1)!}x^{n+1} [/math] so i guess that for x>0 its: [math] R_n(x)=\frac{f^{n+1}©}{(n+1)!}x^{n+1} [/math] for x<0 [math] R_n(x)=-\frac{f^{n+1}©}{(n+1)!}x^{n+1} [/math] should i prove it by induction?? if so then if n=1 then [math] e^x=1+x+ \frac{f^{1+1}©}{(1+1)!}x^{1+1} [/math] but i dont know whats the value of c?? and still it depends on the values of x ??
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