Crash Posted May 19, 2004 Posted May 19, 2004 What is the total resistance of this circut? All the resistors are 10 Ohms so what do you think it is....please show working aswell
Crash Posted May 19, 2004 Author Posted May 19, 2004 Could you please show working? yes the awnser is 14 ohms in the book but i still cant see how it is reached, do you jst use ohms law or more than that? please explain
BPHgravity Posted May 19, 2004 Posted May 19, 2004 Well, it would be alot easier to explain if you had numbered your resistors. I'll give it a shot though. The best way to solve these type of circuits is to first determine what is in parallel and what is in series. Going from left to right, you have 2, 10-ohm resistors in series with each other and are both in parallel with 1, 10-ohm resistor. These three are in series with 1, 10-ohm resistor which is in parrallel with 3 more 10-ohm resistors in series with each other. The 2, 10-ohm in series are added to make 1, 20-ohm resistor, and the other three in series make 1, 30-ohm resistor. The new simplified circuit consists of a 20-ohm in parallel with a 10-ohm, which are in series with a 10-ohm in parallel with a 30-ohm. Using the product over sum method, the parallel resistors can be solved. 20x10/20+10=6.67-ohms, and 10x30/10+30=7.5-ohms. Now all you have left is a 6.67-ohm in series with a 7.5-ohm which can be added to equal the 14-ohms. Make any sense?
Crash Posted May 20, 2004 Author Posted May 20, 2004 Cheers so much it makes heaps of sense, all cheese to be paid to you from now on.
aommaster Posted May 21, 2004 Posted May 21, 2004 BPHgravity would soon become....... the big cheese!
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