Cap'n Refsmmat Posted March 6, 2009 Posted March 6, 2009 (This would ordinarily be in Homework Help, but we are not actually graded on homework and it fits better here.) I have a problem which looks like this: Find all values of x for which the series converges. For these values of x, write the sum of the series as a function of x. [math]\sum^{\infty}_{n = 1} \frac{x^n}{2^n}[/math] I don't really know where to start. Intuition tells me I could just declare x < 2, but I do not know how to go about finding the actual sum of the series or proving that my intuition is actually correct. I'd imagine I am supposed to create a sequence of partial sums and see if the sequence converges (via a limit), but how would I do that for this function?
the tree Posted March 6, 2009 Posted March 6, 2009 The Wikipedia page on geometric series gives you the actual sum. I'd imagine you could take it as a given that [imath]\sum r^n[/imath] converges for [imath]|r|<1[/imath] but that's a question of how much detail is required. Take care with exactly how you write the inequalities - negatives [imath]x[/imath]'s should be included as well.
Cap'n Refsmmat Posted March 6, 2009 Author Posted March 6, 2009 Oh, right, I forgot about rewriting it as [math]\sum_{n = 1}^{\infty} \left(\frac{x}{2} \right )^n[/math] Oops. Thanks for the moment of inspiration.
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