kleinwolf Posted March 29, 2009 Posted March 29, 2009 Starting from [math]E^2=m^2c^4+p^2c^2[/math], then a matrix-type root we get Dirac equation. But here, the term pc is a kinetic term, but not for massive particle, i.e. pc is only for massless. Is it that this equation rules a field with a massive (mc^2) and a massless parts ?
swansont Posted March 29, 2009 Posted March 29, 2009 Starting from [math]E^2=m^2c^4+p^2c^2[/math], then a matrix-type rootwe get Dirac equation. But here, the term pc is a kinetic term, but not for massive particle, i.e. pc is only for massless. Is it that this equation rules a field with a massive (mc^2) and a massless parts ? E=pc only applies to massless particles, but [math]E^2=m^2c^4+p^2c^2 \neq (mc^2+pc)^2[/math], so the kinetic term is not pc
kleinwolf Posted April 1, 2009 Author Posted April 1, 2009 If pc is not a kinetic term, what is then p, the momentum, if it does not depend on the speed ? Is it a quantum quantity proportional to h*k.? In fact my question is : How do we get the term pc ?
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