A Childs Mind Posted April 10, 2009 Posted April 10, 2009 i keep seeing this problem and i dont see how it posible
Shadow Posted April 10, 2009 Posted April 10, 2009 It's not. It's usually a "proof" involving division by zero, or some such nonsense... And I'm not sure this is the right section for this, although I'll leave that to the mods 1
the tree Posted April 11, 2009 Posted April 11, 2009 Or for extremely large values of 2, and bad communication. 1
BigMoosie Posted April 12, 2009 Posted April 12, 2009 Don't be biased; it could also be a very small value of 5, and bad interpretation. 1
samtheflash82 Posted April 12, 2009 Posted April 12, 2009 there is a fallacy in that equation. Merged post follows: Consecutive posts mergedfor some reason the picture didnt show up so here is a link
Kroughfire Posted April 13, 2009 Posted April 13, 2009 The versin of the proof that I've always seen was 1=2, but I'm sure it could be rigged up for 2 + 2 = 5 1=1 -1=-1 -1/1 = 1/-1 root both sides i/1 = 1/i add 3/2i to both sides 3/2i + 1/i = i/1 + 3/2i multiply both sides by i 3/2 + 1 = -1 + 3/2 2.5 = .5 Ok. so it didn't equil 1=2, but its the principle of the thing...
triclino Posted June 23, 2009 Posted June 23, 2009 The versin of the proof that I've always seen was 1=2, but I'm sure it could be rigged up for 2 + 2 = 5 1=1 -1=-1 -1/1 = 1/-1 root both sides i/1 = 1/i add 3/2i to both sides 3/2i + 1/i = i/1 + 3/2i multiply both sides by i 3/2 + 1 = -1 + 3/2 2.5 = .5 Ok. so it didn't equil 1=2, but its the principle of the thing... obviously when you root both sides the result is not :i/1 =1/i ,because : i/1 =1/i <=====> [math] i^2 = 1\Longleftrightarrow -1 = 1[/math] Now the statement, -1 =1 in any line in any proof can result in any conclusion right or wrong For example can result to false statements ,like: 5=7 ,1>4 , [math] x^2<0[/math] ln(-2) = 0 e,t,c ,e,t,c in the following way: -1 =1 [math]\Longrightarrow [(-1 =1 )[/math]or [math](x^2<0)]\Longleftrightarrow[(-1\neq 1)\Longrightarrow (x^2<0)][/math] and since [math] -1\neq 1[/math] we conclude that: [math] x^2<0[/math]
insane_alien Posted July 12, 2009 Posted July 12, 2009 onequestion: that's called rounding error for a reason. what you should have said for the last line is 2 + 2 ≈ 5 which basically means it doesn't equal 5 but its close enough if your tolerance for error is large enough.
onequestion Posted July 12, 2009 Posted July 12, 2009 yes lol i know i realized that obviously its just i didn't want other people to notice since the question originally said "=" not "≈"
alan2here Posted December 24, 2009 Posted December 24, 2009 (edited) A lookup post could help maybe not this one but a lot of thease sorts of things. I'm thinking aloud here. ([math]\neq[/math] 0)/0 = infinite = inf (>0)/0 = inf positively large (<0)/0 = inf negitively large 0/0 = undefined inf (- or /) inf = undefined inf positively large (+ or *) inf positively large = inf positively large inf negitively large - inf negitively large = inf negitively large inf (+ or -) finite = inf undefined (operator or function) anything generally = undefined undefined * 0 = 0 undefined ^ 1 = 1 or -1 anything \ self = 1 Maybe this table is going to get too big. inf = undefined in a way. It's either a range or a set of two ranges. sorry, got a bit off topic. Edited December 24, 2009 by alan2here
jake.com Posted December 25, 2009 Posted December 25, 2009 my teacher showed a way of doing this, using rounding 2+2=5 2.4+2.4= 4.8 round it up and down 2+2=5 2.4 is rounded down to 2 and 4.8 is rounded up to 5.
bascule Posted December 25, 2009 Posted December 25, 2009 There are two methods to prove 2 + 2 = 5 The Orwellian Method The Radiohead Method
uncool Posted December 26, 2009 Posted December 26, 2009 (edited) It's also a joke. 2 + 2 = 5, for very large values of 2... =Uncool- Edited December 26, 2009 by uncool
NeedfulThings Posted December 26, 2009 Posted December 26, 2009 Or you could simply love Big Brother. Yeah, I was wondering if I was the only one having a 1984 flashback.
khaled Posted April 23, 2010 Posted April 23, 2010 if numbers would be real, 2.x + 2.x = 5.xx 2 + 2 ≈ 5 or if numbers have powers, 2^x + 2^y = 5 ..ex: 2^0 + 2^2 = 5 or that it is a false degoma, 2 + 2 = 5 (FALSE) ..etc
wanabe Posted May 21, 2010 Posted May 21, 2010 If in the case 2=2.5 2+2=5 <=> 2.5+2.5=5 Or quite simply the meaning of those numbers is different than what we are used to. So the symbol 2 does not mean two, nor does the symbol 5 mean five. It could also be that the person is using some sort of other numbering system like binary or hex, simply a different base than 10 that we are used to and did not communicate it.
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