Shinok87 Posted May 4, 2009 Share Posted May 4, 2009 Sorry if this is in the wrong section, I am new to the forum. My question is about magnets. I am looking at a few, pull force is about 40 lbs. What does this mean, and how does that relate to the repulsive force? Is there and equation to find out how much two magnets (40 lb pull force) will repel at different distances? Thank you. Link to comment Share on other sites More sharing options...
swansont Posted May 4, 2009 Share Posted May 4, 2009 Pull force is going to be based on some standard material with a given thickness and permeability. I don't know if it is an industry standard, or if various manufacturers might use different standards. According to http://www.kjmagnetics.com/glossary.asp Pull Force - The force required to pull a magnet free from a flat steel plate using force perpendicular to the surface. The limit of the holding power of a magnet. The pull force listed is actual data acquired by testing using our state-of-the-art force test stand. (They go on to provide a table of pull forces for magnets they sell.) Magnets are dipoles and their field drops off as 1/r^3 The torque you get from two dipoles is given here http://en.wikipedia.org/wiki/Magnetic_moment#Forces_between_two_magnetic_dipoles You should be able to discern the force if you know the geometry of the magnet since T = r X F Magnetic calculator based on material and size http://www.magnetsales.com/Design/Calc_filles/PullAndPushBetween2DiscMagnets.asp Link to comment Share on other sites More sharing options...
kensaize Posted April 9, 2010 Share Posted April 9, 2010 hi i'm a regular student fun of magnets. I just wanna ask a question. what is the farthest distance of a magnet (that has a pull force of 193.04lbs.) attracts a 10 gram metal coin? tnx! Link to comment Share on other sites More sharing options...
Amr Morsi Posted April 9, 2010 Share Posted April 9, 2010 Since the question is about "farthest distance", then it is considering gravity. So, equate the force of the magnet to the weight of the coin and find "d". Link to comment Share on other sites More sharing options...
John Cuthber Posted April 10, 2010 Share Posted April 10, 2010 There's not enough data to answer the question. Link to comment Share on other sites More sharing options...
Amr Morsi Posted April 10, 2010 Share Posted April 10, 2010 I think, John, if we have the Magnetic Force Formula, the problem will be solved. Or, do you mean shape of the magnet, susceptibility, .......etc? Link to comment Share on other sites More sharing options...
John Cuthber Posted April 10, 2010 Share Posted April 10, 2010 At the very least, you would need to know about the size of the magnet etc. Also, if the coin is silver then the answer is "never". There are other issues too. The question is not well enough defined to answer it. Link to comment Share on other sites More sharing options...
Amr Morsi Posted April 11, 2010 Share Posted April 11, 2010 (edited) kensaize..... Do you have any additional information? Edited April 11, 2010 by Amr Morsi Link to comment Share on other sites More sharing options...
Amr Morsi Posted August 19, 2011 Share Posted August 19, 2011 [Latex]Pull Force =~ \frac{HPF * Pole} {R^{3}}[/Latex] Where HPF is the Head Pull Force and Pole is peculiar to each substance (magnet or magnetic) and depends upon magnetization and permeability volume, density and shape. This is on the axis of the magnet, and deviates much more away from the axis. Link to comment Share on other sites More sharing options...
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