Neutralization reaction

[Xion]

Hiya, I need some help with this equation:

 

C6H807 + NH3 --> ???

 

I'm not quite sure what product it creates.

 

Any help?

 

Thanks.

[budullewraagh]

i take it this is done in aqueous solution...

 

the NH3 really is NH4OH, so you get (NH4)3C6H5O7+H2O

[Xion]

That's great. Thanks a lot!

[Xion]

Hey budullewraagh,

 

I'm not quite sure about

C6H807 + NH4OH --> (NH4)3C6H5O7+H2O

 

could you clarify where the 3 in (NH4)3C6H5O7+H2O

belongs to? Is it a subscript for (NH4)?

 

Thanks.

[budullewraagh]

yeah it is. the 3 NH4 groups make the compound neutral

[Xion]

hey, I am having trouble neutralizing the reaction now.

 

C6H807 + NH4OH --> (NH4)3C6H5O7+H2O

 

(6C+8H+7O)+(N+4H+O+H) --> (3N +12H) + (6C+5H+70) + h20

 

Can anyone go any further with cancellation?

[budullewraagh]

actually, in ionic form, it's:

 

C6H5O7-3(aq) + 3H+(aq) + NH4+(aq) + OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

[Xion]

Oh I see. Thanks for your help.

[budullewraagh]

anytime

[Xion]

Hmmm.. hey, sorry to bother you again.

 

You said the 3 in (NH4) makes the compound neutral? I don't understand that.

 

It doesn't quite work out when I try to neutralize the equation:

C6H5O7-3(aq) + 3H+(aq) + NH4+(aq) + OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

 

If it's possible, could you try to neutralize it, and give me the neutralized equation so I know if I'm doing it right?

 

Thanks.

[budullewraagh]

i mean neutrally charged. you need the 3 + added because the citrate ion is -3

[Xion]

Oh. Could you please try to get the neutralized form? I can't seem to cancel out right.

[budullewraagh]

neutralized in what way?

[Xion]

Hmm.. the neutralization reaction.

 

I guess the equation would have to be

 

something like: 2H + 2O --> 2H20

 

after you cancel out the compounds.

[budullewraagh]

you mean the acid-base reaction? read above;

C6H5O7-3(aq) + 3H+(aq) + 3NH4+(aq) + 3OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

[Xion]

yes that's right.

[Xion]

I have to cancel out, to get the end product to something like h20. Are you getting any where with that acid-base reaction?

[budullewraagh]

what terms are you speaking on? i dont understand your question. define "getting anywhere"

[Xion]

Are you able to neutralize the acid-base reaction? thats what i meant. Sorry.

 

For example.

 

For KOH + HCI

KOH + HCI --> KCI + H2O

when neutralized by the form of cancellation, it creates:

OH + H --> H2O

 

I have to get:

C6H5O7-3(aq) + 3H+(aq) + 3NH4+(aq) + 3OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

 

to the similar form in the example above.

 

My question is, are you able to neutralize the equation? C6H5O7-3(aq) + 3H+(aq) + 3NH4+(aq) + 3OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

[budullewraagh]

you mean balance it using coefficients?

[aommaster]

That's prbably what he meant. In my terms, it would be "balancing an Ionic equation". I think in all neutralisation reactios, it is (H+)+ (OH-) ---> H2O

 

I put the brackets in so to distinguish each ion!

[Xion]

Yep, i figured it out already. Thanks.

[chemistry]

I'm guessing it is this molecule

 

http://home.tiscali.cz:8080/~cz382002/img/slouc/c6h8o7.gif

 

NH3 will attack the carbonyl carbon, and will result in a salt. Is this organic chemistry? I certainly hope it is not general chemistry.

 

This reaction involves the NH3 ion, so there is no sense in saying that it is ammonium NH4+, whether it takes place in aqueous solution or not.

 

Feel free to ask further questions.

[budullewraagh]

this is organic; hydrogen citrate is definately organic.

NH3 will attack the carbonyl carbon....This reaction involves the NH3 ion

eh, NH3 ion...what charge do you think the N has???