triclino Posted July 24, 2009 Posted July 24, 2009 What theorem or axiom allow us to do the substitutions : x= a + b ,or y= a + b + c, or x= 2y + z^2 e.t.c , e.t.c some times in a mathematical proof ??
ydoaPs Posted July 24, 2009 Posted July 24, 2009 What theorem or axiom allow us to do the substitutions : x= a + b ,or y= a + b + c, or x= 2y + z^2 e.t.c , e.t.c some times in a mathematical proof ?? iirc, it's the symmetric property. If a=b, then b=a.
timo Posted July 24, 2009 Posted July 24, 2009 Closure of a group under the operation(s)? E.g. if a is a real and b is a real then a+b is just another real which you can call it y if you like.
triclino Posted July 27, 2009 Author Posted July 27, 2009 Thanks . But in a system where the primitive symbols are: +,=, and the constants are : 0 ,and the only axioms are : 1) a+ (b+c) = (a+b) + c ,for all a,b,c 2) a+b = b +a ,for all a,b 3) a +0 =a ,for all a the substitution : x= a+b+c ,would be allowed??
timo Posted July 27, 2009 Posted July 27, 2009 (edited) I'd say if there is no guarantee that a+b exists (are you sure that it is not given in your system?) then it makes no sense to substitute it with y or at least not to substitute it with y and assume that y exists (in the system). I don't know what system you are talking about but note that e.g. mathematical groups do have closure under the operation as an axiom . Edited July 27, 2009 by timo ... edit, edit, edit ....
ajb Posted July 27, 2009 Posted July 27, 2009 (edited) The structure looks like a commutative monoid, that is a semigroup with an identity. The "+" looks like an associative binary operation. However, we do not know that the set (I assume we have an underlying set) is closed under "+". You could have a partial function and not a binary opertaion. If your structure is a monoid then x = a+ b + c is fine, with x in your monoid. If your "+" is just a partial function then you have a category. If it is just a category, then you have to specify if a+b (etc.) exists. It is a small category if we have an underlying set. So the question is "2) a+b = b +a ,for all a,b" is that for all a,b or just for a, b if a+b is allowed? Merged post follows: Consecutive posts merged I don't know what system you are talking about but note that e.g. mathematical groups do have closure under the operation as an axiom . As an aside, it is possible to have structures that do not allow the product (composition) of all elements, that is we have a partial function and not a binary operation. The "group like" structure that comes from relaxing the binary operation of groups is called a groupoid. Groupoids are very important in geometry and physics. Edited July 27, 2009 by ajb slightly more detail added
ydoaPs Posted July 29, 2009 Posted July 29, 2009 Thanks . But in a system where the primitive symbols are: +,=, and the constants are : 0 ,and the only axioms are : 1) a+ (b+c) = (a+b) + c ,for all a,b,c 2) a+b = b +a ,for all a,b 3) a +0 =a ,for all a the substitution : x= a+b+c ,would be allowed?? Surely if a=b and b=c, then a=c by the transitive property.
ajb Posted August 1, 2009 Posted August 1, 2009 Surely if a=b and b=c, then a=c by the transitive property. That is absolutely true. More formally, equals is an equivalence relation. However, the question is one of composing all elements or just some. [math]x = a+ b+ c[/math] may not exist. So, I think the question is if the formal system is a monoid or a just a category? (Monoids are themselves categories, but I won't worry about that possible confusion for now.)
the tree Posted August 1, 2009 Posted August 1, 2009 I'd say that for any Magma with + as an operation, if it contains a,b and c then a+b+c should be contained. (a+b) is contained under closure, and (a+b)+c is contained under closure, which generally means a+b+c.
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