devrimci_kürt Posted September 22, 2009 Posted September 22, 2009 1-A jogger travels from x=0 to x=50 m between t=0 and t=10 s.Between t=10 s and t=15 s, the jogger travels from x=50 m to x =25 m. Is the distance traveled by the jogger equal to the magnitude of his displacement (a)between t=0 and t=10 s. (b)=between t=10 and t=15 s?Explain..
insane_alien Posted September 22, 2009 Posted September 22, 2009 first of all, do you know the difference between distance and displacement.
devrimci_kürt Posted September 22, 2009 Author Posted September 22, 2009 of course Distance is the scalar but displacement is the vector ... in other words, Distance is the absolute value of the displacement.. for example, someone walked 3 km and the walked back the 3 km, then distance will be 6 km but displacement will be zero.... is my answer right ?
timo Posted September 22, 2009 Posted September 22, 2009 Distance is the scalar but displacement is the vector ...in other words, Distance is the absolute value of the displacement.. That's not really the same statement with different words. You'd probably call the body temperature of the jogger a scalar, but it certainly isn't the absolute value of the displacement. for example, someone walked 3 km and the walked back the 3 km, then distance will be 6 km but displacement will be zero. Doesn't that contradict your statement that distance is the absolute value of the displacement vector, i.e. the absolute value of the vector (0 km,0 km,0 km) ? is my answer right? It is confused. Hint: The question does not ask for "distance", which can be a lot of stuff (including the magnitude of displacement). It asks for "distance travelled".
devrimci_kürt Posted September 24, 2009 Author Posted September 24, 2009 the absolute value ok, let us forget it in this question, distances and magnitude of displacement are equal... right?
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now