How to find x in the natural logarithm

[dcowboys107]

a.ln(x)-ln(6-x)=3

 

b.log base 2 of (x+5)=log base 2 of (x-5)+log base 6 of (36)+6^(log base 6 of 3)

 

a.ln(x) - ln(6-x) = 3

ln(x/(6-x)) = 3

x/(6-x) = e³

 

I've gotten this far for part a but now I can't solve for x.

 

log[base 2] ((x+5)/(x-5)) = 2 + 3

(x+5)/(x-5) = 2^5

 

Part b I've gotten this far. It says not to give a decimal approximation for any of the problems rather a fraction or an exact expression. Can someone show me how to solve for x in these two problems? Thanks!

[timo]

Multiply with the denominator, (then) solve as normal.

[dcowboys107]

I'm still not getting the answer. . . could you show me step by step?