sxandr6 Posted November 9, 2009 Posted November 9, 2009 f(x)=x + 4 .......x - 3 I know I need to change f(x) to y and then switch x and y. I got that far I tried to multiply both sides by (y-3) in order to solve for y, but after that I got a little lost.
DJBruce Posted November 9, 2009 Posted November 9, 2009 [math]\frac{}{}[/math]So you have: [math]x=\frac{y+4}{y-3}[/math] [math]x(y-3)=(y+4)=xy-3x[/math] Try to isolate all the y's on one side of the equation (Hint distribute the x). Once you have only terms containing y on one side factor something out. Then simply move the x over by dividing.
sxandr6 Posted November 9, 2009 Author Posted November 9, 2009 But wouldn't that elminate the y's. y-y= 3x+4/x Merged post follows: Consecutive posts mergedoh wait nevermind I got it, thanks for your help. 1
thenewb Posted November 19, 2009 Posted November 19, 2009 y+4 = xy - 3x y-xy = -4-3x y(1-x)= -4-3x y=(-4-3x)/(1-x)
DJBruce Posted November 19, 2009 Posted November 19, 2009 (edited) Remember the rules thenewb people are not suppose to completely do the problem for others. You can help guide people, but are not suppose to do it for them. Edited November 19, 2009 by DJBruce Added link.
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