sxandr6 Posted November 9, 2009 Share Posted November 9, 2009 f(x)=x + 4 .......x - 3 I know I need to change f(x) to y and then switch x and y. I got that far I tried to multiply both sides by (y-3) in order to solve for y, but after that I got a little lost. Link to comment Share on other sites More sharing options...
DJBruce Posted November 9, 2009 Share Posted November 9, 2009 [math]\frac{}{}[/math]So you have: [math]x=\frac{y+4}{y-3}[/math] [math]x(y-3)=(y+4)=xy-3x[/math] Try to isolate all the y's on one side of the equation (Hint distribute the x). Once you have only terms containing y on one side factor something out. Then simply move the x over by dividing. Link to comment Share on other sites More sharing options...
sxandr6 Posted November 9, 2009 Author Share Posted November 9, 2009 But wouldn't that elminate the y's. y-y= 3x+4/x Merged post follows: Consecutive posts mergedoh wait nevermind I got it, thanks for your help. 1 Link to comment Share on other sites More sharing options...
thenewb Posted November 19, 2009 Share Posted November 19, 2009 y+4 = xy - 3x y-xy = -4-3x y(1-x)= -4-3x y=(-4-3x)/(1-x) Link to comment Share on other sites More sharing options...
DJBruce Posted November 19, 2009 Share Posted November 19, 2009 (edited) Remember the rules thenewb people are not suppose to completely do the problem for others. You can help guide people, but are not suppose to do it for them. Edited November 19, 2009 by DJBruce Added link. Link to comment Share on other sites More sharing options...
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