The Cancer Cure Posted December 9, 2009 Posted December 9, 2009 Hey guys, Here is the question: A mixture of gases contains 4.14 g of N2, 5.56 g of H2, and 7.06 g of NH3. If the total pressure of the mixture is 5.06 atm, what is the partial pressure of each component? Find the partial pressures of N2, H2, and NH3. Here is my attempt: I took the grams of each one, and converted them into their moles via their grams divided by their molar masses. I added up their mole weights to get one large mole weight. I think took each individual mole weight and divided by the total mole weight. With this percentage, I multipled it by the total pressure, 5.06, to get their partial pressures. What did I do wrong? - Because this isn't working. Thanks guys.
zule Posted December 9, 2009 Posted December 9, 2009 It would be advisable you write here what you have done in numbers. For example, how much do yo think the molar mass of N2 is?
Fuzzwood Posted December 9, 2009 Posted December 9, 2009 Your method is valid, but maybe you are using the wrong molar masses.
The Cancer Cure Posted December 9, 2009 Author Posted December 9, 2009 Okay, I wasn't sure if you minded if I wrote the numbers or not, but I will, sorry. So: Moles 4.14 g N2/28 g mol = 0.147857142857142 moles N2 5.56 g H2/2.0158 g mol = 2.75821013989483 moles H2 7.06 g NH3/17 g mol = 0.415294117647 moles NH3 Total Number of Moles = 3.321361400398972 moles Mole Fractions 0.147857142857142 moles N2/3.321361400398972 moles = ~4.45% 2.75821013989483 moles H2/3.321361400398972 moles = ~83.04% 0.415294117647 moles NH3/3.321361400398972 moles = ~12.50% Partial Pressures .0445 * 5.06 atm = 0.22517 atm of N2 .8304 * 5.06 atm = 4.201824 atm of H2 .1250 * 5.06 atm = 0.6325 atm of NH3 Total atm = 5.059494 atm (Roundoff Error) So...what am I doing wrong? Sorry about not posting numbers earlier! Merged post follows: Consecutive posts mergedWell, now I feel quite dumb. My answers were correct, but I'm using WebAssign, and due to a 1% error because of roundoff error...my answer was incorrect. But since I worked it out again on here with multiple digits held, my answer was correct. I had .224 atm N2 instead of the right answer - .225 atm N2. Well, sorry, thanks for making me right it out though. :doh: Ignore this question, it is resolved.
zule Posted December 9, 2009 Posted December 9, 2009 Why do you think you are doing something wrong? Because of the roundoff error? The roundoff error is logical , because you don't use all the possible decimals.
The Cancer Cure Posted December 9, 2009 Author Posted December 9, 2009 Well, I didn't think I was doing something wrong...but I was getting the answer wrong - so then I thought I had done something wrong. But then I found out it was a couple of decimals.
zule Posted December 9, 2009 Posted December 9, 2009 Ok. I see you have post again while i was reading your previous post. So I see everything is right.
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