Freeman Posted July 17, 2004 Posted July 17, 2004 OK, I know a few, like 'i', but I don't know 'e'. Can someone explain it to me> And tell me if there are any other imaginary numbers?
jordan Posted July 17, 2004 Posted July 17, 2004 e isn't imaginary. There are an infinite number more imaginary numbers (though they can all be expressed in terms of "i" if that's what you mean) Like: sqr(-10) sqr(-43) Basicly, the square root of any negative number is imaginary.
bloodhound Posted July 17, 2004 Posted July 17, 2004 e is just another real constant. its irrational and transcendental. it can be written as a series. sum from n=0 to inf of 1/n! also can be written as a limit e= lim (n tends to inf) (1+1/n)^n and lim (n tends to inf) (1+1/n)^(n+1) the graph below shows the two functions above and the constant value of e
bloodhound Posted July 17, 2004 Posted July 17, 2004 also the exponential function of e . i.e e^x has the special property that its gradient at a point is equal to the value of the function at that point. dont know if there are other functions with this property
JaKiri Posted July 17, 2004 Posted July 17, 2004 it can be written as a series. sum from n=0 to inf of 1/n! This is acquired from putting the property 'when differentiated, it remains the same' into a maclaurin series. It's pretty clear, from this method, that there are no similar numbers.
bloodhound Posted July 17, 2004 Posted July 17, 2004 i am quite unsure. was e discovered first as constant and then e^x being the same as diff e^x or was that condition forced to caculate the value of e
Dave Posted July 17, 2004 Posted July 17, 2004 I think that was the condition, although I could be (and probably am) wrong.
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