Zolar V Posted December 23, 2009 Author Posted December 23, 2009 deuterium will not emit any heat on its own. you'd need a fusion reactor to get any heat and we haven't really built one that can get to a Q>1 level yet(its been done briefly but it wouldn't really be worth it). and this is with massive reactors. with fusion, the bigger the reactor the better. smaller makes it worse. you won't really be able to build an energy generator suitible for the scale of the model. the best would be getting an IC engine for a model plane or similar and hooking it up to an alternator. i realize that with fusion reactors (been folowing it for a few years.. COMMON ITER!) So no little cool looking thermonuclear reactor for my model? .... damn i cant find the sad face icon
Leader Bee Posted December 23, 2009 Posted December 23, 2009 i realize that with fusion reactors (been folowing it for a few years.. COMMON ITER!) If you'd been following it closer you'd know it has been superceded by DEMO ( i'm sure there's still experiments going on with the International Thermonuclear Experimental Reactor but even demo still isn't quite making break even afaik) So there's no fusion reactor that can break even nevermind a miniaturised version that puts out worthwhile energy for the effort.
insane_alien Posted December 23, 2009 Posted December 23, 2009 LeaderBee, DEMO won't be built until after ITER has and then produced useful results. you speak of ITER as if its already up and running but its not. construction is just beignning really and then DEMO will build on knowledge gained from ITER. ITER plans for a Q value of 10 (it will produce 10 time the break even energy) DEMO plans to have a Q value of 25 (25 times greater than break even) breakeven HAS been achieved. but not for long.
Leader Bee Posted December 23, 2009 Posted December 23, 2009 Ahh, Apologies. I figured they'd already started construction on DEMO based on results from ITER. I knew Iter had produced breakeven for miliseconds but mentioned it hadn't been achieved in reference of it never being achieved in a useful manner. Perhaps I should have been a little more clear in my wording. Seems a little strange they would have two very similar experiments running at the same time. What is their reasoning behind already planning DEMO before they have quantifiable results from ITER then? Couldn't there be a possibility this will be an expensive mistake if ITER proves fruitless?
insane_alien Posted December 23, 2009 Posted December 23, 2009 you still seem to be miss informed. ITER hasn't achieved breakeven. this is in no small part due to the fact that right now it hasn't even been built yet. ITER isn't scheduled to be turned on until 2018. 18 years in the future. DEMO is a planned demonstration reactor that will follow ITER. its just planned, they haven't really started doing anything about it at all yet. heck, the conceptual design for DEMO isn't due until 2017, and it isn't due to be completed till 2033. so they will NOT be running at the same time. i suggest you actually go and read up about these projects.
Zolar V Posted December 23, 2009 Author Posted December 23, 2009 you still seem to be miss informed. ITER hasn't achieved breakeven. this is in no small part due to the fact that right now it hasn't even been built yet. ITER isn't scheduled to be turned on until 2018. 18 years in the future. DEMO is a planned demonstration reactor that will follow ITER. its just planned, they haven't really started doing anything about it at all yet. heck, the conceptual design for DEMO isn't due until 2017, and it isn't due to be completed till 2033. so they will NOT be running at the same time. i suggest you actually go and read up about these projects. who is miss informed? i already know the iter hasnt been build, however they have broken ground in france
insane_alien Posted December 24, 2009 Posted December 24, 2009 i was talking about leaderbee, i thought it would be obvious who i was talking to.
Moontanman Posted December 25, 2009 Posted December 25, 2009 "think of a light isotope, decide if it is exothermic and self sustaining Zolar, you keep saying this, it makes no sense to me, exactly what do you mean? deuterium is just hydrogen it produces no more energy on it's own than hydrogen.
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