SR and c measurement

[swansont]

Light takes about .13 seconds to go around the earth.

agreed

 

In that time the earth moves about 0.06 km

This is where you are going wrong.

We are measuring the sagnac effect for a path from A to B on the earth.

 

So, light is not going around the earth. It is going from A to B.

 

Say that distance is 10 km.

 

You will find the sagnac correction higher for the orbit vs the rotation.

 

It is not about now long light takes to move around the circumference.

 

It is about how far light moves while the earth moves.

 

It's about both. If light goes from A to B along the equator you have to know how long it took and how far the point on the earth moved (relative to an inertial reference) in that time. If B represent a point half way around the world, then it's 0.065 seconds, and the earth moves 0.03 km and the Sagnac is 100 ns. If they are 10,000 km apart, then it's 50 ns. If they are 10 km apart, it's 50 ps.

[vuquta]

It's about both. If light goes from A to B along the equator you have to know how long it took and how far the point on the earth moved (relative to an inertial reference) in that time. If B represent a point half way around the world, then it's 0.065 seconds, and the earth moves 0.03 km and the Sagnac is 100 ns. If they are 10,000 km apart, then it's 50 ns. If they are 10 km apart, it's 50 ps.

 

This is what I get for the rotation sagnac.

 

I am still not able to figure out the earth's orbital sagnac.

 

I cannot make it work any way I go about it.

[swansont]

I figured it a few posts back. It'll be about a third of a nanosecond for 10,000 km.

[vuquta]

I figured it a few posts back. It'll be about a third of a nanosecond for 10,000 km.

 

I'll look at it again.

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I figured it a few posts back. It'll be about a third of a nanosecond for 10,000 km.

 

This is the post your mean.

 

http://www.scienceforums.net/forum/showpost.php?p=559741&postcount=99

 

I have already addressed this and proven it wrong.