mehran Posted January 21, 2010 Posted January 21, 2010 If f(x) = x^3 + x + 2 and f(a) = 9 then: Calculate f^{-1}(-5) at "a". This is the question that i'm thinking of it but i can't solve it at all! Does anyone know that how i can get to the answer?
Bignose Posted January 23, 2010 Posted January 23, 2010 Given a f(x), you can find the inverse (if one exists, there certainly doesn't HAVE to be an inverse) by setting y=f(x) and then solving just for x. For example: let f(x) = x^2 +1 Set y = x^2 +1 Then solve for x in terms of y: y -1 = x^2 \sqrt{y - 1} = x Then once you've isolated x, this is the inverse function: x = f^{-1}(y) = \sqrt{y-1}
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