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Posted

If f(x) = x^3 + x + 2 and f(a) = 9 then:

 

Calculate f^{-1}(-5) at "a".

This is the question that i'm thinking of it but i can't solve it at all!

Does anyone know that how i can get to the answer?

Posted

Given a f(x), you can find the inverse (if one exists, there certainly doesn't HAVE to be an inverse) by setting y=f(x) and then solving just for x.

 

For example: let f(x) = x^2 +1

 

Set y = x^2 +1

 

Then solve for x in terms of y:

 

y -1 = x^2

 

\sqrt{y - 1} = x

 

Then once you've isolated x, this is the inverse function:

 

x = f^{-1}(y) = \sqrt{y-1}

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