stevemangles Posted July 30, 2004 Posted July 30, 2004 Why is E1 for He+ 4 times greater than the value for E1 for Hydrgoen This info may help I am following the conditions that: The radius of the ion is inversely proportional to the charge in the nucleus The energy of a particular level is directly proportional to the charge in the nucleus The energy of a particular level is inversely proportional to the radius I also have found two equations En = [1/(n^2)] * E1 & r = (n^2 * h^2)/(4pi^2 * m * k * q^2e) this is where r = radius, n = energy level, h = planks constant, m = mass of electrons, k = 9 x 10 ^9 and qe = charge of electron
swansont Posted July 30, 2004 Posted July 30, 2004 The energy of a level depends on the charge and the radius, which is itself dependent on the charge. If you solve the equations (electrostatic force=centripetal force, angular momentum quantized) you find that the energy depends on the square of the charge of the nucleus. Twice the charge means four times the energy. Here is a derivation of the Bohr model energy equation.
stevemangles Posted July 30, 2004 Author Posted July 30, 2004 thanks...this helps a bit...i hope anyway
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