Guest THarris Posted January 20, 2003 Posted January 20, 2003 The chelate CuQ2- exhibits max absorbance at 580nm. When chelating agent is present in 5 fold excess , the absorbance is dependent only upon the concentration of Cu and obeys beer law over a wide range. Neither Cu or Q absorbs at 580nm. A solution that is 1.40 x 10-4 M in Cu2+ and 6.20 x 10-4 M in Q2- has an absorbance of 0.580 in a 1.00 cm cell at 580 nm. Under the same conditions, a solution that is 1.40 x 10-4 M in Cu2+ and 3.00 10-4 M in Q2 has an absorbance of 0.410. Calculate the formation constant for the process. Cu2+ + 2Q <> CuQ2, Think it has something to do with beer additive law and perhaps simultaneous equations. If someone could help me out on this I would greatly appreciate it. With explanation as well if possible. Regards Thomas Note the subscripts didnt come out right when I posted it.
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