abbyabbigail Posted March 25, 2010 Posted March 25, 2010 Can someone tell me if I am writing this equation right? I am trying to show the ion that is reacting in the solution. The solution: Al2(SO4)3 Equation: Al^+3 + H2O <----> Al(OH)^+2 + H^+
dttom Posted March 27, 2010 Posted March 27, 2010 Al ions exist in hexaqua-form, that is, [Al(H2O)6]3+, so you should start with this. Your direction has been correct.
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