Constant Posted March 28, 2010 Share Posted March 28, 2010 (edited) I have a point charge in a conducting sphere. The charge can be placed anywhere in the sphere & is acted on by the image charge effect & gravity. If the charge touches the side of the sphere within time t it is considered deposited. The image charge is given by: F(x) = -q divΦ(x) Φ = - q 1 4πε0r0 1-R2 r0 is the radius of the sphere. r is the radius at which the charge is at. And R= r/ r0 I’m trying to find the volume of the sphere within which the charge will definitely deposit in time t. I have modelled this situation using excel. Due to symmetry I’m only modelling a quarter of the sphere, (the quarter encompassing the positive & negative z axes, & the positive x & y axis). In my model I put in the initial position of the charge using x, y & z co-ordinates. I’m stuck on which initial positions I need to put the charge in in order to find this volume? I know that this should be quite a simple thing to do but I have really confused myself with this! Thanks Edited March 28, 2010 by Constant Trying to make equation clearer Link to comment Share on other sites More sharing options...
Amr Morsi Posted March 29, 2010 Share Posted March 29, 2010 First, I think that F(x) = -q gradΦ(x), not F(x) = -q divΦ(x), is the correct formula. Second, you have the potential energy of the charge, which when added to the kinetic energy, gives the total energy E, which is a constant. The last equation is function of dr/dt, d(theta)/dt and r. Another equation for theta is r^2 * d(theta)/dt=constant=a, this equation is analogous to conservation of angular momentum. Both differential equations can be solved to find r in terms of t. Try it yourself. Link to comment Share on other sites More sharing options...
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