Constant Posted March 28, 2010 Posted March 28, 2010 (edited) I have a point charge in a conducting sphere. The charge can be placed anywhere in the sphere & is acted on by the image charge effect & gravity. If the charge touches the side of the sphere within time t it is considered deposited. The image charge is given by: F(x) = -q divΦ(x) Φ = - q 1 4πε0r0 1-R2 r0 is the radius of the sphere. r is the radius at which the charge is at. And R= r/ r0 I’m trying to find the volume of the sphere within which the charge will definitely deposit in time t. I have modelled this situation using excel. Due to symmetry I’m only modelling a quarter of the sphere, (the quarter encompassing the positive & negative z axes, & the positive x & y axis). In my model I put in the initial position of the charge using x, y & z co-ordinates. I’m stuck on which initial positions I need to put the charge in in order to find this volume? I know that this should be quite a simple thing to do but I have really confused myself with this! Thanks Edited March 28, 2010 by Constant Trying to make equation clearer
Amr Morsi Posted March 29, 2010 Posted March 29, 2010 First, I think that F(x) = -q gradΦ(x), not F(x) = -q divΦ(x), is the correct formula. Second, you have the potential energy of the charge, which when added to the kinetic energy, gives the total energy E, which is a constant. The last equation is function of dr/dt, d(theta)/dt and r. Another equation for theta is r^2 * d(theta)/dt=constant=a, this equation is analogous to conservation of angular momentum. Both differential equations can be solved to find r in terms of t. Try it yourself.
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