space time curvature

[alejandrito20]

hello

i understand that in a flat space the metric is $\eta_{uv}dx^udx^v$...i know that this means that the light follows straight geodesic in this space time...

 

but ¿what would means that metric is $f(t)\eta_{uv}dx^udx^v$ where f(t)=infinite in t=0 and f(t)=0 in t=infinite.....obvious i understand the matematics, but physically ¿what means?.....for example..¿what means that in bing bang in t=0 f(t)= infinite????

[ajb]

Assuming something like $t =x^{0}$ the metric you present looks conformally equivalent to the Minkowski metric. (Not sure if the $f(t)= 0$ or the $f(t)= \infty$ course trouble, so maybe mod that and the statement that the function is positive).

[alejandrito20]

  ajb said:

Assuming something like $t =x^{0}$ the metric you present looks conformally equivalent to the Minkowski metric. (Not sure if the $f(t)= 0$ or the $f(t)= \infty$ course trouble, so maybe mod that and the statement that the function is positive).

 

yes $t =x^{0}$ , $f(t=0)=\infty$,$f(t=\infty)=0$, f(t) is positive.

 

the metric in t= 0 is $\infty \eta_{uv}dx^u dx^v$, in $t=\infty$ is $0\eta_{uv}dx^u dx^v$.....

 

physically....¿what would mean this???