alejandrito20 Posted April 23, 2010 Posted April 23, 2010 In the einstein equation [math]R_{uv}-0,5 R g_{uv}+ \Lambda g_{uv} = \frac{8\pi G}{c^4}T_{uv}[/tex][/math] i understand that units of [math]g_{uv}=L^2[/math] and then [math]R=\Lambda=\frac{1}{L^2}[/math] ¿[math]R_{uv}[/math] is dimensional less?? [math]G=\frac{L^3}{T^2 M}[/math] and [math]\frac{G}{c^4}=\frac{T^2}{M}[/math] then ¿¿¿[math]T_{uv}=\frac{M}{T^2}[/math]?????
Amr Morsi Posted April 29, 2010 Posted April 29, 2010 I think that the metric tensor is dimensionless and that the unit of the Ricci tensor is L^(-2). By the way, the unit of the stress-energy tensor is the unit of energy per volume.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now