moonflower Posted April 29, 2010 Posted April 29, 2010 The equation F A Q1 Q2 r2 Where A is a constant, Q1 and Q2 are the charges and r is the seperation of the charges. Please can any one offer some assistance in making A the subject of the equation? And to find the units of A
Greippi Posted April 29, 2010 Posted April 29, 2010 Wouldn't A just be the Coulomb constant? Making A the subject is very simple algebra - not sure how I could help without feeding you the answer!
swansont Posted April 29, 2010 Posted April 29, 2010 Rearrange the equation to solve for A (multiply or divide by the other terms, as appropriate). You'll need to know the unit of force (broken down) and the units of charge and distance.
moonflower Posted April 30, 2010 Author Posted April 30, 2010 [r] = m (meter) [Q] = C (Coulomb) [F] = N (Newton) Substituting these units into the above equation gives the unit of A [A] = ? Merged post follows: Consecutive posts mergedcurrent?
swansont Posted April 30, 2010 Posted April 30, 2010 Newtons will need to be broken down, and you have to rearrange the equation. What do you get algebraically if you solve for A?
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