2 = 1?

[Caleb]

Here is a strange equation I found:

a=b

a^2 = ab

a^2 - b^2 = ab - b^2

(a + b)(a - b) = b(a - b)

a + b = b

(a = b)

a + a = a

2a = a

2 = 1

 

This still works, even if you substitute "a" and "b".

 

2 = 2

2^2 = 2(2)

2^2 - 2^2 = 2(2) - 2^2

(2 + 2)(2 - 2) = 2(2 - 2)

2 + 2 = 2

4 = 2

[Cap'n Refsmmat]

You can't divide by a-b. a=b, so a-b=0. Division by 0.

[sammy28]

a=b

a^2 = ab

a^2 - b^2 = ab - b^2

(a + b)(a - b) = b(a - b)

a + b = b

(a = b)

 

 

a + a = a

2a = a

2 = 1

 

2 = 2

2^2 = 2(2)

2^2 - 2^2 = 2(2) - 2^2

(2 + 2)(2 - 2) = 2(2 - 2)

 

2 + 2 = 2

4 = 2

[insane_alien]

a+a=a is only a correct equation if you throw out the rules of maths.

 

starting from something that is false can lead you to any answer you want.

 

of course a could always be zero then its fine. but 2(0) is still zero.

[Sisyphus]

Pretty much all of these types of fake proofs just involve dividing by zero at some point and hoping you won't notice.

[Caleb]

(2 + 2)(2 - 2) = 2(2 - 2)

 

In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you?

[Charlatan]

Here is a strange equation I found:

a=b

a^2 = ab

a^2 - b^2 = ab - b^2

(a + b)(a - b) = b(a - b)

a + b = b

(a = b)

a + a = a

2a = a

2 = 1

 

This still works, even if you substitute "a" and "b".

 

2 = 2

2^2 = 2(2)

2^2 - 2^2 = 2(2) - 2^2

(2 + 2)(2 - 2) = 2(2 - 2)

2 + 2 = 2

4 = 2

 

Two can equal one, but not practically. Theories about two eqaulling one is incorrect.

 

If a = b, and they are different, then there is aporblem with the question. It is false! If one thing equals another, they are just dirrent names. Peter is Paul, for example. That could come from an alias of second name, so, you could say anything and put a question mark behind it!

 

Yes two can equal one, but not pyhsically. Two is a name of something, but, in computer language they cannot be the same. Computer's work off of binary, or, mathematical processors [although Isuggested science based ones], and they will be on or off. One set cannot equal a different set.

[ajb]

In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you?

 

2-2 = 0

 

Division by zero is indeterminate, don't do it!

[Cap'n Refsmmat]

In stead of (2+2) x 0. I just cancelled each of the (2 - 2) out. You can do that can't you?

 

"Canceling out" is division.

 

(a + b)(a - b) = b(a - b)

 

Since (a - b) is 0, b and (a + b) could be anything and the equation would still be true -- each side would still be 0. If a = 2, they'd be 2 and 4, respectively, but the equation would be true. Try to divide out (a - b) and it'd no longer be true.

[Caleb]

"Canceling out" is division.

 

(a + b)(a - b) = b(a - b)

 

Since (a - b) is 0, b and (a + b) could be anything and the equation would still be true -- each side would still be 0. If a = 2, they'd be 2 and 4, respectively, but the equation would be true. Try to divide out (a - b) and it'd no longer be true.

 

Oh, okay. That makes sense. Thanks

[PaulS1950]

and if you don't cancell anything (which you do):

 

Here is a strange equation I found:

a=b

a^2 = ab

a^2 - b^2 = ab - b^2

(a + b)(a - b) = b(a - b) [(2a)(0) = (b)(0)] = 0 = 0

a + b = b.......................reassigned values a + b = 0

(a = b)..........................reassigned values a = b = 0

a + a = a.......................0 + 0 = 0

2a = a..........................2 x 0 = 0

2 = 1...........................0 = 0

 

The simple fact is that zero will almost always cause conflicts which is why it is not a number.

exceptions?:

0/0 = 1 any number divided by itself is 1 (I know)

0n = 0 (I know)

n/0 (if n<>0) = infinity (Yes I know)

 

"I know" = zero is not a number - it is a place holder.

[the tree]

The simple fact is that zero will almost always cause conflicts which is why it is not a number.

*face*

*palm*