mk_2007 Posted May 24, 2010 Posted May 24, 2010 I'm trying to write my lab report up and I'm getting really confused about a certain calculation! I made a 1% agarose gel, and Basically, I added 5 μL of ethidium bromide to a solution (solution= 0.5 g agarose and 50 μL TAE) and the bottle said the ethidium bromide had a concentration of 5 μg/μL. so what concentration of ethidium bromide am I adding to my solution? Help would be much appreciated!
jacky Posted May 24, 2010 Posted May 24, 2010 5 μg/μL of ethidium bromide in 50 μL TAE so in 100μL ?? by calculation: 100x5/50=10 μL
CharonY Posted May 24, 2010 Posted May 24, 2010 You do not add a concentration of EtBr, but you add a certain amount into a volume resulting in a given concentration. Your stock of EtBr has 5µg/µl. You took out 5µl which is a total of 5µg. Then divide that amount by your final volume to get the concentration.
mk_2007 Posted May 25, 2010 Author Posted May 25, 2010 ok. I understand half of that. But why are you taking out 5 μg? I dont understand how you get to that?
ewmon Posted May 25, 2010 Posted May 25, 2010 Final amount = 5 µL × 5 µg/µL = 25 µg. Final volume = 5 µL + 50 µL = 55 µL. Final concentration = 25 µg / 55 µL = 0.455 µg/µL. But you asked what concentration of ethidium bromide you were adding to the solution, and the answer was already written on the bottle: 5 μg/μL.
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