gulalai Posted August 20, 2010 Posted August 20, 2010 i just want some one to explain to me the factors that effect kc and kp of solution
liambob1 Posted August 20, 2010 Posted August 20, 2010 (edited) Kc and kp are effected by: R = gas constant, (0.08206) T = temperature, nP = total moles of gaseous products nR = total moles of gaseous the mathematical relationship between the two constants, Kc and Kp, is: Kp = Kc(RT)^(nP - nR) Edited August 20, 2010 by liambob1
gulalai Posted August 20, 2010 Author Posted August 20, 2010 Kc and kp are effected by: R = gas constant, (0.08206) T = temperature, nP = total moles of gaseous products nR = total moles of gaseous the mathematical relationship between the two constants, Kc and Kp, is: Kp = Kc(RT)^(nP - nR) and if it is just an equilibrium with liquids and solids does moles still effect the constants
liambob1 Posted August 20, 2010 Posted August 20, 2010 If any of the reactants or products are solids or liquids, their concentrations are equal to one because they are pure substances
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