netrat Posted September 3, 2010 Posted September 3, 2010 CONDITION:- If a torch emits a photon with high frequency( high energy "E") another torch emits a photon with very low frequency ( very low energy "e"). Question:- Which torch will get bigger thrust in opposite direction? My Perspective:- According to newtons 3rd law both should get equal thrust because speed of light is constant no matter what the energy. <<<<Please answer>>>>>
swansont Posted September 3, 2010 Posted September 3, 2010 The momentum of a photon is E/c, so the higher energy photon will carry more momentum and give a larger impulse. That's for a single photon. Force is impulse per unit time, so force is E/c multiplied by the number of photons/sec being emitted, which is simply power/time. So for a continuously emitting source, the wavelength does not matter; the power is what is important. i.e. a source of a given power gives the same thrust, regardless of wavelength.
netrat Posted September 3, 2010 Author Posted September 3, 2010 All Right! Thats gona help. Thanks alot.
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