needimprovement Posted September 15, 2010 Posted September 15, 2010 (edited) Can anyone spot the error in this fallacy <prepared>a + b = t <prepared>(a + B )(a - B ) = t(a - B ) <prepared>a^2 - b^2 = ta - tb <prepared>a^2 - ta = b^2 - tb <prepared>a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4 <prepared>(a - t/2)^2 = (b - t/2)^2 <prepared>a - t/2 = b - t/2 <prepared>a = b Therefore all numbers are the same! Edited September 15, 2010 by needimprovement
TonyMcC Posted September 15, 2010 Posted September 15, 2010 (edited) surely line 2 should be ( a+B )( a-B )= a^2 - B^2 ? Edited September 15, 2010 by TonyMcC
D H Posted September 15, 2010 Posted September 15, 2010 Can anyone spot the error in this fallacy Right here. <prepared>(a - t/2)^2 = (b - t/2)^2<prepared>a - t/2 = b - t/2
the tree Posted September 15, 2010 Posted September 15, 2010 You've really got to stop posting such embarrassingly easy 'puzzles'.
needimprovement Posted September 16, 2010 Author Posted September 16, 2010 You've really got to stop posting such embarrassingly easy 'puzzles'. Thank you for your comment.
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