Jump to content

Recommended Posts

Posted (edited)

Can anyone spot the error in this fallacy

 

<prepared>a + b = t

<prepared>(a + B )(a - B ) = t(a - B )

<prepared>a^2 - b^2 = ta - tb

<prepared>a^2 - ta = b^2 - tb

<prepared>a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4

<prepared>(a - t/2)^2 = (b - t/2)^2

<prepared>a - t/2 = b - t/2

<prepared>a = b

 

Therefore all numbers are the same!

Edited by needimprovement
Posted

Can anyone spot the error in this fallacy

Right here.

 

 

<prepared>(a - t/2)^2 = (b - t/2)^2

<prepared>a - t/2 = b - t/2

 

 

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.