anthropos Posted November 6, 2010 Posted November 6, 2010 "Treatment of 3-methylcyclohexene with HCl yields 2 products, 1-chloro-3-methylcyclohexane and 1-chloro-1-methylcyclohexane. Draw a mechanism to explain the result." I can't really figure out one can arrive at 1-chloro-1-methylcyclohexane, how did the positive charge manage to shift to the CH3 position? Also, I read another textbook, and it features a question which states that "reaction of HBr with 3-methylcyclohexene yields a mixture of four products: cis- and trans-1-bromo-3-methylcyclohexane and cis- and trans-1-bromo-2-methylcyclohexane". Then shouldn't the HCl reaction yield products of similar structure? Thank you.
mississippichem Posted November 6, 2010 Posted November 6, 2010 -Remember, carbocations will rearrange to obtain a more stable configuration. -More electron donating groups lead to higher stability. -Cl- will attack this carbocation after rearrangement. -You're starting with a secondary carbocation after the addition of H+. Is there any way a tertiary carbocation can arise? Maybe this will point you in the right direction.
Horza2002 Posted November 11, 2010 Posted November 11, 2010 Mississippichem has given you some great advice there. And remember that bromine is a lot larger than chlorine so its nucleophilic properties are different to that of chlorine
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