1123581321 Posted November 30, 2010 Posted November 30, 2010 I was wondering, if gravity in general relativity is the result of the curvature of space/time. Then how can the effect at the earth surface for which we all feel be accounted for, since space/time is being warped due to our presence on the earths surface is it... Because isn't general relativity only describing the topology of space external to the earth - as in the universe at large..
ajb Posted November 30, 2010 Posted November 30, 2010 I was wondering, if gravity in general relativity is the result of the curvature of space/time. Then how can the effect at the earth surface for which we all feel be accounted for, since space/time is being warped due to our presence on the earths surface is it... Because isn't general relativity only describing the topology of space external to the earth - as in the universe at large.. The gravitational field surrounding the Earth is approximately the Schwarzschild metric. This solution is a vacuum solution and does not describe the interior of the Earth. General relativity says practically nothing about topology, it is a local description of curvature.
D H Posted November 30, 2010 Posted November 30, 2010 General relativity says practically nothing about topology, it is a local description of curvature. Sure it does. Mean sea level is a constant time dilation surface.
lemur Posted November 30, 2010 Posted November 30, 2010 I don't see why a geodesic path through spacetime has to be located at a minimum distance from a planet/moon/star/etc. Granted, an object traveling at orbital speed at a terrestrial altitude just high enough not to bump into mountains would quickly lose speed from air-resistance or burn up from the friction. But if a satellite was accelerated to orbital speed 10m above the surface of the moon or some other gravity-well without atmosphere, wouldn't the orbit constitute a geodesic path?
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