Jump to content

Recommended Posts

Posted

Hi

 

Anyone good with statistics ? I just want to confirm something, not asking for answers.

 

The standard error of the mean SEM, is it the square root of standard deviation or is it standard deviation divided by the square root of n, the sample number.

 

Please can someone clarify, i have a test and I dont want to do the wrong thing.

Posted (edited)

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

Edited by DJBruce
Posted

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

 

Actually, n should be replaced by (n-1). But that does not matter when n>>1

 

Ludwik Kowalski (see Wikipedia)

Posted

Yes that is correct. For a sample of size n with sample standard deviation S, the standard error of the mean is

 

[math] SE = \frac{S}{\sqrt{n}}[/math]

 

so it is the square root of standard deviation ? or the second one

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.