Time on?

[Gareth56]

Firstly sorry if this is in the wrong forum and secondly sorry if my question is so simple, it's just that I cannot get my ilogical head around it.

 

I have an appliance that's on for 3mins and off for 5 mins and what I want to work out (but am having great difficulty doing) is how long the appliance is on for during a 24 hour period.

 

Thanks

[TonyMcC]

Three fifths of 24.

0.6 * 24 = 14.4 hours

0.4 of an hour = 0.4 * 60 = 24 minutes.

Time on is therefore 14 hours and 24 minutes.

[ash.bekah]

864 minutes

Edited December 26, 2010 by ash.bekah

[swansont]

Three fifths of 24.

0.6 * 24 = 14.4 hours

0.4 of an hour = 0.4 * 60 = 24 minutes.

Time on is therefore 14 hours and 24 minutes.

 

A good example for why you check the reasonableness of your work: this can't be right, since it's off longer than it's on, and you have an answer saying the opposite.

 

On for three and off for five is on 3/8 of the time.

[Gareth56]

So if I understand the logic behind this, it's the (time on)/(time on + time off)?

 

So it's basically a simple fraction question and solution?

 

 

Thanks.

[cypress]

But only because one day is evenly divisible by the cycle time = (time on + time off). If it were not evenly divisible, you would have had to work out the remainder and figured the amount of time on and off during that last partial cycle.

[TonyMcC]

A good example for why you check the reasonableness of your work: this can't be right, since it's off longer than it's on, and you have an answer saying the opposite.

 

On for three and off for five is on 3/8 of the time.

Oh my gosh!!! Thank you swansont and sorry everyone else - lol

Edited December 26, 2010 by TonyMcC