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Construct a molecular orbital diagram. [(Bonding orbitals)-(antibonding orbitals)]/2 gives the bond order. Here is an example for [ce] F_2 [/ce]:

 

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3 bonding orbitals (two [math] \sigma [/math] and one [math] \pi [/math]) minus two antibonding orbitals ([math] \sigma^*[/math] and [math] \pi^* [/math]) equals bond order of 1 which makes sense for the singly bonded difluorine. And yes, there can be fractional bond orders like the 0.5 bond order of [ce] Li_2 [/ce].

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