Mystic in percentage?

[Mystery_of_GodST]

How come if I make a square 1 metre big and put an object that takes up 2% of the square it would still fit in the square whether it was spread out then made into just length or width

 

but if I put an object that took 99.9% of the square then made it into just length or width it would defeat the square

 

It's like mystic in percentage or something

 

Don't know?

[michel123456]

"and put an object that takes up 2% of the square it would still fit in the square whether it was spread out then made into just length or width" is wrong.

 

or

 

I don't understand what you mean.

[Mystery_of_GodST]

Say you made a square 10 cm big on 4 sides

 

and put an object thats 3 cm, no matter how much you try and move the object in the square it will still remain in the square, its smaller than the square. in the drawing on the left with the attached pic

 

but if you put an object in the square thats 9.9 cm of the area of the square, and u move the object around in length or width, it will pass the square, and thats smaller than the square too

 

why does the 9.9cm object pass the square in length or width, and the 3 cm one doesn't

[michel123456]

The small object can move as much as its difference with the square, I mean 10 cm minus 3 cm= 6 cm in width & length as you say. The same goes for the big object: it can move 10 cm minus 9,9 cm = 0,1 cm. Where is the mystery?

[Mystery_of_GodST]

if both objects are smaller than the box they can stay in the box true

 

the mystery is

 

some objects can stay in the box in LENGTH and WIDTH

 

but the bigger objects will exceed the boundaries of the Box if you just make them in LENGTH or WIDTH

 

i want to know why SOME stay in the box no matter what

 

and some will exceed the boundaries of the box

Edited January 5, 2011 by Mystery_of_GodST

[michel123456]

Objects A & B are smaller than the square and extend out of it.

Edited January 5, 2011 by michel123456

[Mystery_of_GodST]

if you move the lines i guess you can make them exceed the boxs perameter without any doubt...

 

but my question is , if BOTH the objects are smaller than the box and only 1 exceeds the boundaries is my question

 

if you take one objects thickness (width and length together) and made it into a line, for example the L if you take its length and width and just make them into one line, it will exceed the box, if it is an L i understand it will stay in the box but if you make it into "LENGTH" only or "WIDTH" whatever u want, it will leave the box

 

why does only ONE of them exceed the box's perameter and not the next

 

check the pic below

Edited January 5, 2011 by Mystery_of_GodST

[michel123456]

Again, what is the mystery?

[Mystery_of_GodST]

Again, what is the mystery?

 

I want to know why the box on the bottom exceeds the box, and why the top doesn't. i can't figure it out... shouldnt they both fit in the box because they are smaller than it..... ??????? where does the point that comes in that says This will exceed the box's limit?

Edited January 5, 2011 by Mystery_of_GodST

[Bignose]

One doesn't fit inside the other because area isn't just limited to squares or circles or other regular shapes. As you noted, something with an area of 1 m^2, and take many different shapes. Another way of putting that is that just because something as a given area, doesn't set its perimeter in any way whatsoever. Unless additional information is given, for a set area A, there are an infinite number of shapes that can have that area.

Edited January 5, 2011 by Bignose

[Sisyphus]

Your confusion seems to come from not distinguishing between length and area. For example, when you say "3 cm object," do you mean an object that is 3 cm long, or an object that has an area of 3 cm?

 

Or, I also don't know what you're talking about. I don't see what mystery you're talking about.

[Mystery_of_GodST]

Okay i'll try and explain this the best I can

 

Say a square was 10 cm big (that would be 10 cm on 4 sides of the square)

If I placed an object that took up 9.9 cm length and width of the 10 cm square,

If I placed an object that took up 3 cm length and width of the square,

Now if I took the object that was 9.9cm in length and width, and just made it as a line, it would definatley pass the square's boundaries of 10 cm

 

But if I took the object that was 3 cm of the square in length and width, and made it into a line, it would stay in the square's boundaries

 

My question is... Why does the 3 cm object stay in the box and the 9.9cm doesn't stay in the square after making them both into thin lines when they are both smaller than the square

Edited January 6, 2011 by Mystery_of_GodST

[michel123456]

Okay i'll try and explain this the best I can

 

Say a square was 10 cm big (that would be 10 cm on 4 sides of the square)

If I placed an object that took up 9.9 cm length and width of the 10 cm square,

If I placed an object that took up 3 cm length and width of the square,

Now if I took the object that was 9.9cm in length and width, and just made it as a line, it would definatley pass the square's boundaries of 10 cm

 

But if I took the object that was 3 cm of the square in length and width, and made it into a line, it would stay in the square's boundaries

 

My question is... Why does the 3 cm object stay in the box and the 9.9cm doesn't stay in the square after making them both into thin lines when they are both smaller than the square

 

No. It does not go that way.

 

First, a line is a geometrical entity that has no surface. a line of 10 cm length has no surface because surface needs a second dimension (a width) that a line (in geometry) do not possess. When you reduce the width of a surface so that it becomes oblong and look like a line, you always get a surface. When you reduce the width of any surface and gets zero width, you obtain a line of infinite length, like any other line.

 

Now, when you put a width to your line, from a geometrical point of vue, it is not a line anymore, it is a surface.

Then you can have a surface of 10 cm long & 3 cm width (30cm^2) that will fit into your square. But you can also have a surface of 100 cm long and 0,3 cm width, equal to the precedent (30cm^2), that will not fit into the square.

Edited January 6, 2011 by michel123456

[Bignose]

 

 

But if I took the object that was 3 cm of the square in length and width, and made it into a line, it would stay in the square's boundaries

 

 

Why can't you make a "line" 3 cm and 10000 cm long and then it wouldn't fit...

 

The point is, like michel wrote, you need to define was "made it into a line" means? Is is a function from [math]R^2[/math] to [math]R^1[/math]? Do you mean, given a rectangular object of area A, and a length L, find what the W is? And so on.