alpha2cen Posted January 6, 2011 Posted January 6, 2011 (edited) Let's think about this problem. This operation @ is consisted of two of multiplying or dividing plus one constant a(a=/ 0). a @ a= a 2 @ 3a = 2/3 2a@ 2 = a^2 1 @ 1 = ? hint @ : ( ) # ( ) # ( ) where ( ) means constant or variables where # means multiplication or division. The first operator searching problem. Edited January 7, 2011 by alpha2cen
the tree Posted January 8, 2011 Posted January 8, 2011 I'm going to guess that x@y = x*a/y, so 1@1=a, but I wouldn't be able to say if that's a unique solution or not.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now