Spyros13 Posted February 10, 2011 Posted February 10, 2011 Simplify this Boolean expression : F(a,b,c)=((c+a)' *(c⊕b)')' My answer is:F= ((c'*a')*(cd+c'd'))'=(c'*a')'+(cd+c'd')'=c+a+(c'd'*cd)=c+a Is that right? If not explain?
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