ahmeeeeeeeeeed Posted February 16, 2011 Posted February 16, 2011 Hello I want to ask.. When there is a circuit ( battery - Rheostat -lamb) When we decrease the Rheostat .. the current will increase But momently there will be a self induced current which will weaken the current I want to know >> momently , which one will beat the other ?? And why ? And If we increase the Rheostat , the current will decrease .. but there will be a self induced current which will strengthen it >> which will beat ?? AND why ??
swansont Posted February 16, 2011 Posted February 16, 2011 Hello I want to ask.. When there is a circuit ( battery - Rheostat -lamb) When we decrease the Rheostat .. the current will increase But momently there will be a self induced current which will weaken the current I want to know >> momently , which one will beat the other ?? And why ? And If we increase the Rheostat , the current will decrease .. but there will be a self induced current which will strengthen it >> which will beat ?? AND why ?? The self-induction can be viewed as an induced reactance (resistance). It slows the rate of increase (or decrease) of the current, but it doesn't "win." battery - Rheostat -lamb. mmmm... roast lamb.
SMF Posted February 16, 2011 Posted February 16, 2011 If Ahmeeeeeeeeeed has an incandescent lamb (another interesting image) the changing resistance of the filament with temperature also has to be taken into account. Resistance is low in a cold filament so a lot of current flows, but when it heats up and is bright its resistance increases and current reduces. SM
alpha2cen Posted February 17, 2011 Posted February 17, 2011 Using constant voltage electric source is good for this kind of test. When we use a battery, the battery capacity and chemical reaction rate affect the test result. When the resistance of the filament is small, much current flows. As the result voltage dropping phenomena occurs.
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