hkus10 Posted February 26, 2011 Posted February 26, 2011 (edited) 1) Find a vector equation for the plane in R3(3D) with scalar equation 2x − 3y + z = 5 . First,I find three points on the plane and then I used one point as a fixed point in order to find two vectors on the plane by using two other points. Then, I tried to test whether the two vectors are perpendicular to the normal vector of this plane by using cross product. However, I do not get the right normal vector by using my two vectors on the plane? My question is that whether my approach is wrong? If yes, what should I do? Edited February 26, 2011 by hkus10
the tree Posted February 26, 2011 Posted February 26, 2011 Then, I tried to test whether the two vectors are perpendicular to the normal vector of this plane by using cross product. However, I do not get the right normal vector by using my two vectors on the plane?I'm a little confused here: if you're testing your normal using the cross product, then how are you finding it in the first place? A cross product of any two vectors vectors on the plane should give a perfectly good normal vector.
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