98% v/v H2SO4

[peanutbutterpig]

i got 98% v/v H2SO4 and the density is 1.02g/cm3.

 

how am i able to find the concentration of H2SO4??

 

and once i find the concentration, how much H2SO4 do i need in 100ml solution of 0.1M?

 

help me thanks.

[Horza2002]

Removed so as not to just give the anwser without showing you the method; see next post.

Edited March 1, 2011 by Horza2002

[insane_alien]

you aren't supposed to just give away the answer, you should at the very most show them the methodology

[Horza2002]

I didn't give the methodology since I have always been told what the various percentages translate to for concentration...just assumed that was the same everywhere.

 

The density you have given is wrong; 98% sulphuric acid is 1.83g/ml. Ok so heres the method you need to use in the attached file.

 

Once you have the concentration of the stock solution, you should easily be able to calculate what you need.

Volume.pdf

Edited March 1, 2011 by Horza2002

[CharonY]

You want the molarity of the solution (i.e. mol/L). You have the density (which is off). You have the volume. You still need the molecular weight.

 

Edit: cross-posted.

Edited March 1, 2011 by CharonY

[peanutbutterpig]

the density here is g/cm3 but the pdf given is g/ml.

is there any difference??

[Horza2002]

Millilitres (ml) and centimeters cubed (cm³) are the same thing. It is just my persoanl prefernce to do my workings out in ml not cm³ .

[peanutbutterpig]

Ok thanks. How about finding the dilution?? How to calculate the volume used of H2SO4 given that the final concentration of the solution is 0.05M and the final volume is 100ml.

[Horza2002]

Calculate now many moles you need for 0.05M solution. Then work out how much of the concentrated acid you need. It will be good for you to do this yourself; I will be very happy to check them for you if you post them.