PoWW Posted March 2, 2011 Posted March 2, 2011 Hi there, I hope I have placed this question in the right area. I am trying to workout the rule(s) to the below numbers. Sorry about the ---, but only way to line up numbers. I have managed to workout that if x=y then the result = x*1.414 I have also managed to workout that if x or y = 1 then the result (example if x=1) = y+(x/y)/2 I haven't managed to workout anything else. If you can give me a few tips or direct me in the right way, I would much appreciate it. Thanks for all your help in advance Vincent X 10--10.05--10.20--10.44--10.77--11.18--11.66--12.21--12.81--13.45--14.14 -9---9.06---9.22---9.49---9.85--10.30--10.82--11.40--12.04--12.73--13.45 -8---8.06---8.25---8.54---8.94---9.43--10.00--10.63--11.31--12.04--12.81 -7---7.07---7.28---7.62---8.06---8.60---9.22---9.90--10.63--11.40--12.21 -6---6.08---6.32---6.71---7.21---7.81---8.49---9.22--10.00--10.82--11.66 -5---5.10---5.39---5.83---6.40---7.07---7.81---8.60---9.43--10.30--11.18 -4---4.12---4.47---5.00---5.66---6.40---7.21---8.06---8.94---9.85--10.77 -3---3.16---3.61---4.24---5.00---5.83---6.71---7.62---8.54---9.49--10.44 -2---2.24---2.83---3.61---4.47---5.39---6.32---7.28---8.25---9.22--10.20 -1---1.41---2.24---3.16---4.12---5.10---6.08---7.07---8.06---9.06--10.50 -0---1.00---2.00---3.00---4.00---5.00---6.00---7.00---8.00---9.00--10.00 Y
imatfaal Posted March 2, 2011 Posted March 2, 2011 (edited) Try squaring each figure and seeing how it relates to the x and y (and to x^2 and y^2). I think you will quickly work it out then. if not I will post the answer Edited March 2, 2011 by imatfaal
PoWW Posted March 2, 2011 Author Posted March 2, 2011 Try squaring each figure and seeing how it relates to the x and y (and to x^2 and y^2). I think you will quickly work it out then. if not I will post the answer Wow, I am impressed how quickly you have resolved this. Sorry, but it has been a long while since I played with maths, so very rusty. I did think it would have something to do with your suggestion, but it just isn't happening for me. Just so I'm heading in the right path, I need to find the square root of each figure and try and find the relationship it has with x and y. So for example taking where x=5 & y=5 the result is 7.07. Square root of result = 2.658947. I like you approach btw
imatfaal Posted March 2, 2011 Posted March 2, 2011 Hello Poww - no you have it the wrong way around. What I said was take the square of each of number - so for x=4 y =4 you would take 5.656854 (or whatever number of decimals you have) and square it to give 32. Now try and figure a connection between 4, 4 and 32 - now see if this connection will work for another cell. BTW we normally call x the variable that goes across the page and y the vertical one. 1
PoWW Posted March 2, 2011 Author Posted March 2, 2011 Hello Poww - no you have it the wrong way around. What I said was take the square of each of number - so for x=4 y =4 you would take 5.656854 (or whatever number of decimals you have) and square it to give 32. Now try and figure a connection between 4, 4 and 32 - now see if this connection will work for another cell. BTW we normally call x the variable that goes across the page and y the vertical one. Right, understand and will go try that out. Thanks about the x&y positions. I did say it has been rather a long time since enjoying the challenges of maths. Thank you ever so much for your help. I have finally figured out the answer. Result = square root of (x squared + y squared) I actually feel a little intelligent. Is there a way I can spend you praise for the handling of this question?? 1
imatfaal Posted March 2, 2011 Posted March 2, 2011 Poww - glad to help. Once I saw 1.414 (square root of two jumps out at you) and 14.14 (ie ten times the sqrt2) then the route to the answer was pretty clear. And I guess you have already sent me praise (many thanks) by hitting the green plus badge at the bottom right hand corner of my posts.
Mr Skeptic Posted March 2, 2011 Posted March 2, 2011 Incidentally, that formula is very important. It is the formula for distance if you know the x and y offsets, or if you prefer for the hypotenuse of a right triangle (which is the best kind of triangle).
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