hkus10 Posted March 10, 2011 Posted March 10, 2011 Determine whether the given vector A in 2x2 matrix belongs to span{A1, A2, A3}, where A1 = [1 -1 0 3] A2 = [1 1 0 2] A3 = [2 2 -1 1] A = [5 1 -1 9]. Since A1, A2, A3 are not a nx1 matrices, I cannot put this into reduced echelon form? Therefore, what can I do to solve this problem? Thanks
timo Posted March 10, 2011 Posted March 10, 2011 You write down a condition for A being an element of span{A1,A2,A3} and see if the resulting equations can be satisfied.
acidhoony Posted March 16, 2011 Posted March 16, 2011 you may got c1A1 + c2A2 + c3A3 = (a b) (c d) which a,b,c,d are arbitary real number maybe~ if you can find c1,2,3for every a,b,c,d then it A1,2,3 is span all 2 by 2 Matrix. but i think it will not span. Because a,b,c,d is fourrr v variable but so we need at least for basis but we have only A1,2,3 ; only three ;;; i don;t know it is dependent or not , but , whatever it is it is too little number of matrix to span every two by two matrix~
the tree Posted March 16, 2011 Posted March 16, 2011 (edited) The simplest, crudest approach is to write it as a set of linear equations and look for a solution from there. If [imath]c_1 A_1 + c_2 A_2 + c_2 A_2 = A[/imath], then that implies four equations that can be reduced using good old fashioned elimination. The more mathsy approach would be to summarise the the set described by [imath]\mbox{span}( A_1 , A_2 , A_3 )[/imath] in such a way that it's obvious whether or not [imath]A[/imath] is included. As Acidhoony said, that set is going to be at most 3-dimensional. Edited March 16, 2011 by the tree
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now