divinum1 Posted November 28, 2011 Author Posted November 28, 2011 ! Moderator Note You've been invited to present evidence in support of this before. Forum rules demand that claims be supported with evidence. Failure to comply will result in thread closure, which will preclude you from bringing the subject up again. It's put-up or shut-up time. Any orbiting body is subject to the orbital force of the body around which it orbits. Orbit of the Moon for example is bound to Earth orbital force whose magnitude is directly proportional to the mass of the earth, G, and the distance between the two bodies, as follow; v = (mG)/d (square rooted) , Where v matches the velocity of the orbital force at that particular distance. And the velocity of the force is = m/s. (not meters/second/second, as centripetal force is) Furthermore orbital force is circular in form due to the division of space between the two forces. And for this reason, all orbital motions are circular. Hence orbital force, centripetal force, and the distance between them are always proportional to one another. Fo= Fcxd (square rooted), Fc= Fo2/d, and d=Fo2/Fc ,
Klaynos Posted November 28, 2011 Posted November 28, 2011 Any orbiting body is subject to the orbital force of the body around which it orbits. Orbit of the Moon for example is bound to Earth orbital force whose magnitude is directly proportional to the mass of the earth, G, and the distance between the two bodies, as follow; v = (mG)/d (square rooted) , Where v matches the velocity of the orbital force at that particular distance. And the velocity of the force is = m/s. (not meters/second/second, as centripetal force is) Furthermore orbital force is circular in form due to the division of space between the two forces. And for this reason, all orbital motions are circular. Hence orbital force, centripetal force, and the distance between them are always proportional to one another. Fo= Fcxd (square rooted), Fc= Fo2/d, and d=Fo2/Fc , Ignoring, for now, all the stuff about orbital force, which appears to be junk, what you seem to be saying is that circular motion is motion in circles because it's circular motion... I'm thinking this is a little bit of circular reasoning... Gravity acts ONLY in the direction towards the mass. There is no force in the tangential direction. You need some pretty impressive evidence if you claim otherwise, which you appear to be doing. There is STILL no evidence.
swansont Posted November 29, 2011 Posted November 29, 2011 Any orbiting body is subject to the orbital force of the body around which it orbits. Orbit of the Moon for example is bound to Earth orbital force whose magnitude is directly proportional to the mass of the earth, G, and the distance between the two bodies, as follow; v = (mG)/d (square rooted) , Where v matches the velocity of the orbital force at that particular distance. And the velocity of the force is = m/s. (not meters/second/second, as centripetal force is) Furthermore orbital force is circular in form due to the division of space between the two forces. And for this reason, all orbital motions are circular. Hence orbital force, centripetal force, and the distance between them are always proportional to one another. Fo= Fcxd (square rooted), Fc= Fo2/d, and d=Fo2/Fc , ! Moderator Note As this is just a re-re-restatement of your position, one must conclude you have no evidence to support it. As per the rules, this thread is closed. Do not start any new threads on the topics or hijack other threads with it.
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